dont know wat i m gonna do for the exam... 😕 have to find som1 real inteligent sit next to me........... hopefully 😉
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so far we have got to 5 coins
Five coins have a total of 32 permutations: H = Head & T = Tail
5 H's 4 H's 1 T 3 H's 2 T's 2 H's 3 T's 1 H 4 T's 5 T's
still working on it my colleagues done a weird pascal triangle table thing
the other colleague matt says its 7 chances out of 64
steve is still working on it
ok star here is the formula my colleagues have sorted i hope this helps cos i am stumped i get it but only a little
To work out the number of permutations of Y heads out of N coins you use the formula:
N! / (Y! x (N-Y)!)
This gives 28 where N is 8 and Y is 6.
So, there are 28 permutations of 8 coins with 6 heads.
Now, with each coin there are 2 possible results (heads or tails). As there are 8 coins, the number of potential combinations is 2^8 which is 256.
So, we have a probability of 28/256, which cancels down to 7/64.
i hope this helps star i really do