Karthik met with an accident?

OMG😲😲😲 in the last scene karthik is comng in the car wen a truck comes from the opposite direction. karthik asks the driver to drive carefully as the truck is coming towards them. However both vehiclew come face to face and karthik shouts out. Not sure wat happened. This karan has crossed the limits😡. nandu is now suspicious of karan. Wen suman is trying to put the flower on the entrance karan purposely hits the stool 😡so that suman falls into his arms. nandu sees this and is confused. Family has prepared for the reception function and this last scene is taking palce. Dont know wat happened to karthik.😭 Karthik has also signed a bond paper thnking it is a deal wen RM comes dressed in a suit😆😆 along with other three persons posing as fake clients. karthik thnks he has finalized the deal. bah why dont they read the papers before signing.😡

thks Hema, so nothing more happened today, & Karthik met with accident😭, hope nothing happens to him😭

Thank u Hema 4 the update S= a( r to the power n minus 1 ) times ……….1

R minus 1

where a= first term of the geometric progression[G.P]- 3,9,27,81,243,729,…… and so on upto 50 terms. [note here only 6 terms r shown].

a = first term which is 3

r = common ratio which is 3 in the above sequence.

n = number of terms in the sequence which is equal to 50.

Now putting n=50,a=3,r=3 in eq 1 we get

S= 3( 3 to the power 50 minus 1)…………2

3 minus 1

Solving eq 2 we get S = 1076846981537778883155372

Therefore thanks 1076846981537778883155372 times.

Now hema please don't add something [that is x] to this 25 digit number and say welcome 1076846981537778883155372 + x times…..lol.🤣🤣🤣🤣🤣🤣

thanks hema....

Originally posted by: kaabarz

Thank u Hema 4 the update S= a( r to the power n minus 1 ) times '''.1

R minus 1

where a= first term of the geometric progression[G.P]- 3,9,27,81,243,729,'' and so on upto 50 terms. [note here only 6 terms r shown].

a = first term which is 3

r = common ratio which is 3 in the above sequence.

n = number of terms in the sequence which is equal to 50.

Now putting n=50,a=3,r=3 in eq 1 we get

S= 3( 3 to the power 50 minus 1)''''2

3 minus 1

Solving eq 2 we get S = 1076846981537778883155372

Therefore thanks 1076846981537778883155372 times.

Now hema please don't add something [that is x] to this 25 digit number and say welcome 1076846981537778883155372 + x times'..lol.🤣🤣🤣🤣🤣🤣

although this is for hema......thanks a lottttttttttttt kavya🤗.....for considering my request..😳

yaa, in initial epi also, it was said that he is like dada ji😆

thnx hema for the quik update...dont even feel like watching this sad episode now :(

Originally posted by: kaabarz

Thank u Hema 4 the update S= a( r to the power n minus 1 ) times ???.1

R minus 1

where a= first term of the geometric progression[G.P]- 3,9,27,81,243,729,?? and so on upto 50 terms. [note here only 6 terms r shown].

a = first term which is 3

r = common ratio which is 3 in the above sequence.

n = number of terms in the sequence which is equal to 50.

Now putting n=50,a=3,r=3 in eq 1 we get

S= 3( 3 to the power 50 minus 1)????2

3 minus 1

Solving eq 2 we get S = 1076846981537778883155372

Therefore thanks 1076846981537778883155372 times.

Now hema please don't add something [that is x] to this 25 digit number and say welcome 1076846981537778883155372 + x times?..lol.🤣🤣🤣🤣🤣🤣

Ashu suman picked the phone that karan had left and atteneded it. That joker spoek saying that half the job has been done and only the other half has to be done...hearing this suman is confused but karan grabs it and says it is wrong number.

What papers did Karthik sign?