how is this possible?😲

a+a = a+x [add a to both sides]
2a = a+x [a+a = 2a]
2a-2x = a+x-2x [subtract 2x from both sides]
2(a-x) = a+x-2x [2a-2x = 2(a-x)]
2(a-x) = a-x [x-2x = -x]
2 = 1 [divide both sides by a-x]
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1how is this possible?😲

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Originally posted by: pure_choclate
how is this possible?😲
and one more examplea = x [true for some a's and x's]
a+a = a+x [add a to both sides]
2a = a+x [a+a = 2a]
2a-2x = a+x-2x [subtract 2x from both sides]
2(a-x) = a+x-2x [2a-2x = 2(a-x)]
2(a-x) = a-x [x-2x = -x]
2 = 1 [divide both sides by a-x]do you guys think its a mistake?😛
Originally posted by: AsliiGuy
for me math = 🤢
wowowo!
really tho, i think they are using the power of factoring and distribution division then -+ like numbers with the same variables to get the end result..😃
Originally posted by: Lead-Oxide
I was already confused and now I'm even more confused. 😕😆 Math is just not my thing...
Originally posted by: Lead-Oxide
I was already confused and now I'm even more confused. 😕😆 Math is just not my thing...
Originally posted by: pure_choclate
how is this possible?😲
and one more examplea = x [true for some a's and x's]
a+a = a+x [add a to both sides]
2a = a+x [a+a = 2a]
2a-2x = a+x-2x [subtract 2x from both sides]
2(a-x) = a+x-2x [2a-2x = 2(a-x)]
2(a-x) = a-x [x-2x = -x]
2 = 1 [divide both sides by a-x]do you guys think its a mistake?😛