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cindy

@madeforme

Inactive

+ 2

Posted: 16 years ago

#111

does anybody have information about multiple sclerosis. plz help me

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Aishwarya

@muffins2waffles

Inactive

+ 5

Posted: 16 years ago

#112

Hi, my 7th grade cousin needs help with this problem, but I'm busy with my own homework to explain it to her. Please help her.

Solve the Iniquality.

The Cookie Factory has a fixed cost of $300 per month plus $0.45 for each cookie sold. Each cookie sells for $0.95. How many cookies must be sold during one month for the profit to be at least $100.

Thank you.

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akhl

@akhl

Dazzler

Posted: 16 years ago

#113

Originally posted by: MusicalAiswarya

Solve the Iniquality.

The Cookie Factory has a fixed cost of $300 per month plus $0.45 for each cookie sold. Each cookie sells for $0.95. How many cookies must be sold during one month for the profit to be at least $100.

Thank you.

Let number of cookies sold = n

Fixed cost = $300

Selling cost = n * $0.45

Total cost = $300 + n * $0.45

Income = n * $0.95

Income - total cost = profit

Profit >= $100

n * $0.95 - ($300 + n * $0.45) >= $100

n * $0.95 - $300 - n * $0.45 >= $100

n * $0.50 - $300 >= $100

n * $0.50 >= $100 + $300

n * $0.50 >= $400

n >= $400/$0.50

n >= 400/0.50

n >= 800

The minimum value of n, which satisfies the above in equality = 800

Ans: 800

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riahboo33

@riahboo33

Inactive

Posted: 16 years ago

#114

chemistry- A gas occupies a volume of 2.50 L at a pressure of 350.0 kPa. If the temperature remains constant, what volume would the gas occupy at 1750 kPa?

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akhl

@akhl

Dazzler

Posted: 16 years ago

#115

Originally posted by: riahboo33
chemistry- A gas occupies a volume of 2.50 L at a pressure of 350.0 kPa. If the temperature remains constant, what volume would the gas occupy at 1750 kPa?

V1 = 2.50 L
P1 = 350.0 kPa
P2 = 1750 kPa
V2 = ?

T is constant.
Boyle's law:-
P1 * V1 = P2 * V2
V2 = P1 * V1/P2
V2 = (350.0 kPa) * (2.50 L)/(1750 kPa)
V2 = 0.500 L

Ans: 0.500 L

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x~kasamh_se~x

@x~kasamh_se~x

Inactive

Posted: 16 years ago

#116

how do u analyse something?

i need help with analysing

isha

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samera12

@samera12

Explorer

Posted: 16 years ago

#117

Hi I need help with my chemistry homework..i cant seem to figure this out.. I actually dont get this topic.. so i would really appreciate if someone helps me out..Thanks alottt!!

1. Amonium ions and nitrate ions react in water to form nitrogen gas.
NH4(aq) + NO2(aq) ----> N2 (aq) + 2H2O (I)

The following experimental data was recorded:

Experiment Initial [NO2] mol/l Initial [NH4) Initial Rate (mol/l.s)

1 0.0200 0.200 1.10 x 10 E -6

2 0.0100 0.200 5.40 x 10 E -7

3 0.200 0.0202 1.08 x 10 E -7

4 0.200 0.0404 4.36 x 10 E-7

5 0.300 0.0200 ?

6 ? 0.250 6.20 X 10 E-5

a) What is the order of the reaction with respect to NH4?

b)What is the rder of the reaction with respect to NO2?

c) Write the rate law for the reaction.

d) What is the K for the reaction?

e)What is the rate of exxperiment 5?

f) What is the [NO2] in experiment 6?

2. Give the rate law for the following equation is rate = K[A] [B2]

Sugeest a mechanism for the reaction.

3. Assume the N2) and O2 react according to the rate law

R = K[N2O] [O2]

How does the rate change if :

a) The concentration of O2 is doubled?

b) The volume of the enclosing vessel is recuded by half?

c) The temperature is decreased?

Edited by samera143 - 16 years ago

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akhl

@akhl

Dazzler

Posted: 16 years ago

#118

Hi Samera,
For some days, I was not visiting this forum. Now I visited and saw this question. Just a few days back, I clarified exactly the same topic to a student. I will give you the solution in a few hours as I am doing some other work now.

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samera12

@samera12

Explorer

Posted: 16 years ago

#119

hey akhl.. i would really appreciate your help :)

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akhl

@akhl

Dazzler

Posted: 16 years ago

#120

Hi I need help with my chemistry homework..i cant seem to figure this out.. I actually dont get this topic.. so i would really appreciate if someone helps me out..Thanks alottt!!

1. Amonium ions and nitrate ions react in water to form nitrogen gas.
NH4(aq) + NO2(aq) ----> N2 (aq) + 2H2O (I)

The following experimental data was recorded:

Experiment Initial [NO2] mol/l Initial [NH4) Initial Rate (mol/l.s)

1 0.0200 0.200 1.10 x 10 E -6

2 0.0100 0.200 5.40 x 10 E -7

3 0.200 0.0202 1.08 x 10 E -7

4 0.200 0.0404 4.36 x 10 E-7

5 0.300 0.0200 ?

6 ? 0.250 6.20 X 10 E-5[/quote]

a) What is the order of the reaction with respect to NH4?
Let the order of reaction with respect to NH4 = m,
rate of experiment i = ri

In experiments 3 and 4, [NO2] are equal. Therefore, in these experiments, ri is proportional to [NH4]^m
r4/r3 = ([NH4] in experiment 4/NH4 in experiment 3)^m
(4.36 * 10^-7)/(1.08 * 10^-7) = (0.0404/0.0202)^m
4.04 = (2.00)^m
m = log(4.04)/log(2.00) = 2.01
Thus the order of reaction with respect to NH4 = 2.01

b)What is the rder of the reaction with respect to NO2?
Can you solve this? Note that in reactions 1 and 2, {NH4] are equal.

c) Write the rate law for the reaction.
From b, you can find order with respect to NO2. Let it be n.
Then write rate law as
rate = K * [NH4]^m * [NO2]^n
Just put the values of m and n.

d) What is the K for the reaction?
Substitute values from any experiment in rate law. You can calculate K.

e and f also can be solved by putting values in the rate law.

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