I don't think so you are suppose to put your homework problems to this forumā¦its to discuss the showā¦so next time don't do it you are not allowed..i don't know where can you get homework help here but don't post it hereā¦but still since you have test tomorrow I will help you outā¦
Wow..thats an easy problemā¦.here is the solutionā¦
Okay so first of all find the common denominator for only x over y plus y over x and the common denominator is xy so it would be X āY/ x2 + y2 over xy (once again the common denominator is xy)
And then just divide the y/x^2 + y^2 over xy and since its dividing you change the sign and flip so it would be X ā Y time XY over x^2 + y^2
after then you multiply and you get X ā x(y^2) over x^2 + y^2 and you still have to do everything to Xā¦common denominatior and its X^2 + Y^2 (you know why right..since we multiplied everything it changed)
So after then its: x(x^2+y^2) ā x(y^2) over x^2 + y^2 and then distribute and you get x^3 + x(y^2) ā x(y^2) over x^2 + y^2 and then xy^2 and āxy^2 cancel out so its x^3 over x^2 + y^2 and that's your answer
Problem # 2:
The common denominator is c-1 for both..all you have to do is multiplyā¦once you multiply c-1 to 1 (both on the top and bottom 1) you should get 1+C-1 (which is C cuz 1-1 is 0) over c-1 divide by c-1-1 (which is C-2 cuz -1-1 is -2) over c-1 and since its dividing its reciprocalā¦so its C over c-1 times c-1 over c-2 and c-1 (s) cancel out and you are left with c over c-2
I already did all these in pre-calc..its really easy hun...at first its confusing but at the end its easy..even i had it when i was a junior...you are in GT right since you have it in ur junior year..its normally in ur senior year...lol...but i love HS math its pretty easy...i did all these 3 years ago..lol...i am in college and i did this in my freshman year of college...its pretty easy...
Edited by pm rocks - 17 years ago