Chemistry anyone???

Hey guys i am reallyy sorry i knw its really boring to do chemistry in your summer vacations but yeaahh i have a problem can any1 find me a solution to dis question?

hahaha np i see 10 people have viewed but no answer...dats okaayyy 😊

I did not answer because just now I opened this thread. Now, let me answer. I love Science. But, please tell me if my answer is wrong.

The balanced equation can be written as follows: -

CaSO4.2H20 -> CaSO4.(2-n)H20 + n H2O

CaSO4.(2-n)H20 is plaster of paris.
On the left hand side, there are 2 moles of water. On the right hand side, we assume that n moles of water are released as steam. Therefore, there are 2-n moles of water in plaster of paris.

Atomic wights: -
Ca = 40
S = 32
O = 16
H = 1

Note: - For simplicity, I have used approximate values. Actual values are slightly different. But the above values will serve the purpose for this problem.

Molar weight of
CaSO4.2H20 = (40+32+16*4) + 2*(1*2+16)
= 136 + 36 = 172

Molar weight of H2O = 1*2 + 16 = 18

From the equation: -
172 gm of gypsum releases 18n gm of water.
Or, 100 gm of gypsum releases
18n * 100/172 gm of water

From data given in problem: -
18n * 100/172 = 15.7
Or,
n = (15.7 * 172)/(18*100) = 1.5

Therefore, formula of plaster of paris is
CaSO4.(2-n)H20
= CaSO4.(2-1.5)H20
= CaSO4. 0.5H20

Thank you ssooooo muchhh and yup its the rite answer..i was half way thruu but cudnt get the ending partt thnx alottttt

good one... my brain also started working after seeing this equation