GOTW: Sciene and tech game - Page 6

Originally posted by: bhopalyellow

This value is more than 1N, applied force

So the friction force will adjust itself to 1N and the Book will not move and remain stationary

So value of friction force= 1N and direction opposite to applied force

rajnish bhaiya/akhl bhaiya.......plz wud anyone of u explain this last part of the question...i'm not getting it.....😕

oops i thought this que is part of game and answered. but this is for jasleen. so edited😃😃

Originally posted by: akhl

Jasleen,

Maximum value of static friction = coefficient of static friction * normal force

Here coefficient of static friction = 0.2

and normal force = 10 N

Therefore coefficient of static friction * normal force = 0.2 * 10N = 2 N

But note that this is the maximum value of static friction. Actual value is equal to this or less than this. If any less value is enough to stop the book from sliding, then static friction is as much as is needed to stop the book from sliding.

I push the book with 1N. This means that if table applies 1N force in opposite direction, then it is enough to stop the book from sliding. So static friction = 1N.

_____________________

Suppose I change the question a little bit.

I push the book with 3N force. Other data remain as earlier. Do you know what will happen in this case?

Note: This question is not a part of the game. So no points on it. So do not worry whether your answer will be right or wrong. It is only for your learning.

😊

[quote=akhl]Jaslees,

i think.......the relative speed=speed (moving table - book)

untill here you are corect jasleen. the force of friction is 2 N. but question is not solved completely. you need to calculate acceleration too. so try to calculate acceleration😊