Bigg Boss 19 - Daily Discussion Topic - 20th Sep 2025 - WKV
🏏T20 Asia Cup 2025: India vs Oman, 12th Match, Group A at Abu Dhabi🏏
Deepika starts shooting for King
Yeh Rishta Kya Kehlata Hai Sept 20, 2025 Episode Discussion Thread
🏏 Asia Cup 2025: Sri Lanka vs Bangladesh, Super Four, Match 1 Dubai🏏
Anupamaa 20 -24 Sept 2025 Written Update & Daily Discussions Thread
Singer Zubeen Garg Passes Away
Fav contestant this year?
Book Talk Reading Challenge & Book Bingo ~ Oct 2025 Sign up open!
Downfall is Real! No one even cares for SPA pics this year
Star Parivaar Ki Favourite Saas
Related new fanfics
Homebound - OSCARS 2026 Official Indian Entry
Yeh Rishta Kya Kehlata Hai Sept 21, 2025 Episode Discussion Thread
Akshay Kumar Is Back To Giving Hits
“Why aren’t Bollywood actresses supporting Deepika? - Upala KBR
HONEYMOON🏩 20th and 21.9
Chunkey Panday happiest for Ahaan’s success (Saiyaara)
H-1B Visa Crisis: Families Forced to Return, Futures at Stake
Tabu likes a reel shading Deepika on Instagram
Originally posted by: mayu1982
What a lovely post soni
Dil khush kar diya..time to do some mastiNow coming to your postWhy Devakshi failed to maintain distanceUsing mathematicsNowBasic formula -Speed= Distance/TimeDistance = Speed * Tiime --------------1Now most of time they are touching when they are at rest ..So we need to calculate the rest timeNow coming to basic formula againt'= t/ square root ( 1- v(square of 2)/ c(square of 2)
where
t'= change in time
t= rest time
v = velocity
c= speed of light
rest time = change in time * square root of ( 1- velocity (square of 2) / Speed of light ( square of 2) ------2
Now
The coefficient of restitution is a number which indicates how much kinetic energy (energy of motion) remains after a collision of two objects. If the coefficient is high (very close to 1.00) it means that very little kinetic energy was lost during the collision.
Coefficient of restitution = Speed of separation/ Speed of approach
e= v2- V1/ U2- U1
Speed of approach = Speed of separation/Coefficient of restitution.---3
Now putting this values in equation 1 we get
Distance ={ change in time * square root of ( 1- velocity (square of 2) / Speed of light ( square of 2) ------2} * Speed of separation/Coefficient of restitution--------------------- 4
Now we got the formula of distance ..
Next part I will show you how this formula is responsible for not keeping nice distance between the two.
Now looking at the formula itself you can see speed of separation and velocity of light is major reason for their less maintained distance 😳
P.S> Sorry for doing this. ALthough I want to do more.. But someone else is responsible for my incomplete work. U know the name very well😡😡 Jyoti
Originally posted by: JyotiBThakur
And why on earth my name popped up from nowhere. 😡😡 What have i done to your mathematics gyaan? 😡
Originally posted by: LoveAnushka
Moni Di!!!!Kahan gayab ho gayi aap!Koi miss kare ya nahi, but I really missed these funny posts...Btw, when will you continue your Waqt ne kiya FF... I really looked up to it & followed...Please cont. soon...Btw, this distance thing, subah kehkar, 1 ghante main bhool bhi gaye...Distance truly works but opposite... Jiske saath rakhna hai i.e. DevAkshi who toh hua nahi magar kissi aur ke saath zaroor kaam kiya i.e. DevAkshi & Ishwari...😆Looks like this works opposite way!We want more of these type posts as aaj kal bohot serious mmahol yahan ka...😃Love,Anushka
Originally posted by: JyotiBThakur
Anushka Dear. Waqt ne Kiya is not Moni's FF. It's Mayu's FF... Sachme lagta hai aapne Moni ko bahot zyada hi miss kiya hai... Sab kuch miz kardiya 😆😆😆And DevAkshi ne to Maintaining distance ka new meaning nikala hai kal 😆😆
Originally posted by: LoveAnushka
Sorry! haan Sorry Moni Di! Its mayu Di's FF!Ye do naam hai iss poore forum main jinn main main sabse jyaada phansti hoon I always get confused & mix up their names...Ek baar already ye galti ho chukka hai...🤣🤣🤣Thanks Jyoti Di!Haan Ki naam hi miss kardiya, so okay ye mayu di ke liye that she needs to cont. her FF😆Who bhi hai... Kal ka kaha kal, aaj main bhul jaana kehte hai magar ye dono toh 2 minute pehle kahi baat ko 2 minute main bhul jaana formula hai...
Originally posted by: mayu1982
<font face="Verdana, Arial, Helvetica, sans-serif" size="3" color="#0000ff">What a lovely post soni</font>
<font face="Verdana, Arial, Helvetica, sans-serif" size="3" color="#0000ff">
</font><font face="Verdana, Arial, Helvetica, sans-serif" size="3" color="#0000ff">Dil khush kar diya..</font><font face="Verdana, Arial, Helvetica, sans-serif" size="3" color="#0000ff">
</font><font face="Verdana, Arial, Helvetica, sans-serif" size="3" color="#0000ff">time to do some masti</font><font face="Verdana, Arial, Helvetica, sans-serif" size="3" color="#0000ff">
</font><font face="Verdana, Arial, Helvetica, sans-serif" size="3" color="#0000ff">Now coming to your post</font><font face="Verdana, Arial, Helvetica, sans-serif" size="3" color="#0000ff">
</font><font face="Verdana, Arial, Helvetica, sans-serif" size="3" color="#990000">Why Devakshi failed to maintain distance</font><font color="#990000" face="Verdana, Arial, Helvetica, sans-serif" size="3">Using mathematics</font><font color="#990000" face="Verdana, Arial, Helvetica, sans-serif" size="3">
</font><font face="Verdana, Arial, Helvetica, sans-serif" size="3" color="#990000">Now</font><font face="Verdana, Arial, Helvetica, sans-serif" size="3" color="#ff00ff">
</font><font face="Verdana, Arial, Helvetica, sans-serif" size="3" color="#ff00ff">Basic formula -</font><font face="Verdana, Arial, Helvetica, sans-serif" size="3" color="#ff00ff">
</font><font face="Verdana, Arial, Helvetica, sans-serif" size="3" color="#ff00ff">Speed= Distance/Time</font><font face="Verdana, Arial, Helvetica, sans-serif" size="3" color="#ff00ff">
</font><font face="Verdana, Arial, Helvetica, sans-serif" size="3" color="#ff00ff">Distance = Speed * Tiime --------------1</font><font face="Verdana, Arial, Helvetica, sans-serif" size="3" color="#0000ff">
</font><font face="Verdana, Arial, Helvetica, sans-serif" size="3" color="#0000ff">Now most of time they are touching when they are at rest ..</font><font face="Verdana, Arial, Helvetica, sans-serif" size="3" color="#0000ff">
</font><font face="Verdana, Arial, Helvetica, sans-serif" size="3" color="#0000ff">So we need to calculate the rest time</font><font face="Verdana, Arial, Helvetica, sans-serif" size="3" color="#0000ff">
</font><font face="Verdana, Arial, Helvetica, sans-serif" size="3" color="#ff00ff">Now coming to basic formula again</font><font face="Verdana, Arial, Helvetica, sans-serif" size="3" color="#ff00ff">t'= t/ square root ( 1- v(square of 2)/ c(square of 2)</font>
<font face="Verdana, Arial, Helvetica, sans-serif" size="3" color="#ff00ff">where</font>
<font face="Verdana, Arial, Helvetica, sans-serif" size="3" color="#ff00ff">t'= change in time</font>
<font face="Verdana, Arial, Helvetica, sans-serif" size="3" color="#ff00ff">t= rest time</font>
<font face="Verdana, Arial, Helvetica, sans-serif" size="3" color="#ff00ff">v = velocity</font>
<font face="Verdana, Arial, Helvetica, sans-serif" size="3" color="#ff00ff">c= speed of light</font>
<font face="Verdana, Arial, Helvetica, sans-serif" size="3" color="#0000ff">
</font><font face="Verdana, Arial, Helvetica, sans-serif" size="3" color="#0000ff">
</font><font face="Verdana, Arial, Helvetica, sans-serif" size="3" color="#660099">rest time = change in time * square root of ( 1- velocity (square of 2) / Speed of light ( square of 2)------2</font>
<font face="Verdana, Arial, Helvetica, sans-serif" size="3" color="#0000ff">
</font><font face="Verdana, Arial, Helvetica, sans-serif" size="3" color="#0000ff">Now</font>
<font color="#990000" face="Verdana, Arial, Helvetica, sans-serif" size="3">Thecoefficient of restitutionis a number which indicates how much kinetic energy (energy of motion) remains after a collision of two objects. If thecoefficientis high (very close to 1.00) itmeansthat very little kinetic energy was lost during the collision.</font>
<font color="#990000" face="Verdana, Arial, Helvetica, sans-serif" size="3">
</font><font face="Verdana, Arial, Helvetica, sans-serif" size="3" color="#ff00ff">Coefficient of restitution = Speed of separation/ Speed of approach</font>
<font face="Verdana, Arial, Helvetica, sans-serif" size="3" color="#ff00ff">e= v2- V1/ U2- U1</font>
<font face="Verdana, Arial, Helvetica, sans-serif" size="3" color="#ff00ff">Speed of approach = Speed of separation/Coefficient of restitution.---3</font>
<font face="Verdana, Arial, Helvetica, sans-serif" size="3" color="#ff00ff">
</font><font face="Verdana, Arial, Helvetica, sans-serif" size="3" color="#ff00ff">Now putting this values in equation 1 we get</font>
<font face="Verdana, Arial, Helvetica, sans-serif" size="3" color="#ff00ff">
</font><font color="#660000"><font face="Verdana, Arial, Helvetica, sans-serif" size="3">Distance ={</font>change in time * square root of ( 1- velocity (square of 2) / Speed of light( square of 2)------2} *Speed of separation/Coefficient ofrestitution--------------------- 4</font>
<font color="#660000">
</font><font color="#660000">Now we got the formula of distance ..</font>
<font color="#660000">
</font><font color="#660000" face="Verdana, Arial, Helvetica, sans-serif" size="3">Next part I will show you how this formula is responsible for not keeping nice distance between the two.</font>
<font color="#660000" face="Verdana, Arial, Helvetica, sans-serif" size="3">
</font><font color="#660000" face="Verdana, Arial, Helvetica, sans-serif" size="3">Now looking at the formula itself you can see speed of separation and velocity of light is major reason for their less maintained distance😳</font>
P.S> Sorry for doing this. ALthough I want to do more.. But someone else is responsible for my incomplete work. U know the name very well😡😡Jyoti<font face="Verdana, Arial, Helvetica, sans-serif" size="3" color="#ff00ff">
</font>