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Nupur/Nupsi

@NupurMJHT4u

Inactive

Posted: 13 years ago

#471

What does sustainability mean? (environment)

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596277

Suspended

Posted: 13 years ago

#472

@ akhl thanks so much, im sure its talking about the thin converging lens as well, could you explain why they are equal? and for the converging mirror it asks for the image distance, so Im confused:\

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akhl

@akhl

Dazzler

Posted: 13 years ago

#473

Originally posted by: -Ayeshaa-
@ akhl thanks so much, im sure its talking about the thin converging lens as well, could you explain why they are equal? and for the converging mirror it asks for the image distance, so Im confused:\

They are equal because when the lens is thin, then the light ray is inside the lens for a very short time. So it does not matter whether the light ray enters from one direction or the other - the difference between focal lengths will be negligible.

For convergins mirror, may be "image distance" is typo in question. But if it is really image distance, then also you can answer "near focal point". This is because near focal point, the image is very small, so it is difficult to locate.

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596277

Suspended

Posted: 13 years ago

#474

^ thank you soo much Akhl :)

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akhl

@akhl

Dazzler

Posted: 13 years ago

#475

Do u have formula for speeds of transverse and longitudinal waves in a spring?

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596277

Suspended

Posted: 13 years ago

#476

^ umm no I never got any formulas, we just did an experiment for the wave thing. We used a small spring slinky and a big slinky. We tested the longitudinal and transverse waves on them.

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akhl

@akhl

Dazzler

Posted: 13 years ago

#477

I also think the answer should be small diameter spring for both types of waves. This is because when the diameter is small, then vibration has to travel smaller circumference, so it can move from one loop of the spring to the next faster.

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Sonia

@Miggi

Inactive

Posted: 13 years ago

#478

Hello, I need help in this question. I would really appreciate if someone helps me ASAP.

The radius of a wheel is 0.500 m. A rope is wound around the outer rim of the wheel. The rope is pulled with a force of magnitude 5.00 N, unwinding the rope and making the wheel counter-clockwise about its central axis. Ignore the mass of the rope. a) How much rope unwinds while the wheel makes 1.00 revolution? b) How much work is done by the rope on the wheel during this time? c) What is the torque on the wheel due tothe rope? d) What is the angular displacement anglein radiansans, of the wheel during 1.00 revolution? e) Show that the numerical value of the work done is equal to the product (torque*angle).

Thanks in advance.

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akhl

@akhl

Dazzler

Posted: 13 years ago

#479

Originally posted by: Miggi
Hello, I need help in this question. I would really appreciate if someone helps me ASAP.

The radius of a wheel is 0.500 m. A rope is wound around the outer rim of the wheel. The rope is pulled with a force of magnitude 5.00 N, unwinding the rope and making the wheel counter-clockwise about its central axis. Ignore the mass of the rope. a) How much rope unwinds while the wheel makes 1.00 revolution? b) How much work is done by the rope on the wheel during this time? c) What is the torque on the wheel due tothe rope? d) What is the angular displacement anglein radiansans, of the wheel during 1.00 revolution? e) Show that the numerical value of the work done is equal to the product (torque*angle).

Thanks in advance.

a) d = 1.00 * (2 * pi * r) = 1.00 * (2 * 3.14 * 0.500) = 3.14 m
b) F.d = 5.00 * 3.14 = 15.7 J
c) r F = 0.500 * 5.00 = 2.50 N.m
d) 2 pi = 2 * 3.14 = 6.28 rad
e) Torque * angle = 2.50 * 6.28 = 15.7 N.m
Work done = 15.7 J (from answer of part b)
Their numerical values are equal.

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596277

Suspended

Posted: 13 years ago

#480

Hey, I need help with this physics equation. I think I did the first half correct I just need help solving for g. If you could show it on paint or something that would be great.

http://imageshack.us/f/717/solveforg.jpg/

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